8 | |9 |Floor |20 |0.9 | |10 |Ceiling |15 |0.7 | By utilising the given information, calculations nuclear number 18 to be carried out to interpret the value of heat transfer at the window, positioned at 6. To do this, the consider below needs to be puzzle out. [pic] This is to be work by setting up a matrix comparison in the form of [M][J] = [S] Where [M] is a squ ar matrix and its elements are given by [pic] Derivation of Configuration Factors 12-56, 12-78, 34-56 and 34-78 A12F12-56 = A1F1-6 + A1F1-5 + A2F2-5 + A2F2-6 For F12-56, X = 4, Y = 3, Z = 6 [pic] [pic] From Figure 5.4 (Notes), F12-56 = 0.26 For F1-5, X = 2, Y = 3, Z = 6 [pic] [pic] From figure 5.4 (Notes), F1-5 = 0.218...If you collar to get a ripe essay, order it on our website: Orderessay
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